SOLUTION: How much pure water must be mixed with 2 liters of a 40% solution of antifreeze to get a 25% antifreeze solution?
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Question 261021: How much pure water must be mixed with 2 liters of a 40% solution of antifreeze to get a 25% antifreeze solution?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.4*2=.25x
8/10=x/4
10x=32
x=3.2 liters
to be added
.4*2=.25*3.2
.8=.8
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