SOLUTION: A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t^2 + 512t + 64. Find the height of the shell 30 seconds after it is fired. (Simplify the answer as m
Algebra.Com
Question 259732: A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t^2 + 512t + 64. Find the height of the shell 30 seconds after it is fired. (Simplify the answer as much as possible.)
Could someone help me with this problem?
Thank you.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
plug in 30 for t
s=-16t^2 + 512t + 64
s = -16 (t^2-32 t-4)
s = -16*(30^2-32(30)-4)
s = -16(-2(30)-4)
s=-16*(-64)
s=1024
RELATED QUESTIONS
A mortar shell is s feet above the ground after t seconds, where
f(t) = −16t2 + 512t... (answered by ikleyn)
A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t2 + 512t... (answered by Alan3354)
At a fireworks stand show, a 3 in shell is shot from a mortar at an angle of 75 degree.... (answered by Glaviolette)
when a 10-in. shell is shot from a mortar at an angle of 75 degrees, the height, y (in... (answered by Alan3354)
a bullet shot straight up is s feet above the ground in t seconds
[[[[where... (answered by checkley75)
The polynomial - 16t2 + 120t gives the height, in feet, reached by a fireworks shell in t (answered by richard1234)
The height in feet of a fireworks shell can be modeled h(t) = -16t2+224t , where t is the (answered by solver91311)
A fireworks shell is shot straight up with an initial velocity of 80 feet per second. Its (answered by lwsshak3,Alan3354,stanbon)
Boudreaux is hunting quail with his shotgun on a platform 16 feet above the ground. The... (answered by stanbon)