SOLUTION: This problem says soybean meal is 16% protein, cornmeal is 8% protein. How many poundsof each should be mixed together in order to get 320-lb. mixture that is 10% protein. How man

Question 250120: This problem says soybean meal is 16% protein, cornmeal is 8% protein. How many poundsof each should be mixed together in order to get 320-lb. mixture that is 10% protein.
How many pounds of cornmeal ?
How many pounds of soybean meal?
Im so totally lost please help. thanks
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
This problem says soybean meal is 16% protein, cornmeal is 8% protein.
How many pounds of each should be mixed together in order to get 320-lb. mixture that is 10% protein.
;
How many pounds of cornmeal ?
How many pounds of soybean meal?
:
Let x = amt of soy which is 16% protein
The total mixture is given as 320 lb, therefore
(320-x) = amt of cornmeal which is 8%
:
Using the decimal equiv we have:
.16x + .08(320-x) = .10(320)
:
Multiply what's inside the brackets
.16x + 25.6 - .08x = 32
:
.16x - .08x = 32 - 25.6
:
.08x = 6.4
x =
x = 80 lb of soy
then
320 - 80 = 240 lb of corn meal required
;
;
Check solutions in original equation
.16(80) + .08(240) = .10(320)
12.8 + 19.2 = 32; confirms our solutions
:
Has this helped you find your way through the "mixture problem" forest?
If you learn this method, you can do most of these kind of problems.
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