SOLUTION: write the equation of a line that is prependicular to the given line and that passes throught the given point. 4x-12y=2;(10,-1)

Question 249114: write the equation of a line that is prependicular to the given line and that passes throught the given point.
4x-12y=2;(10,-1)
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Perpendicular to 4x-12y=2 & passing through (10,-1)
4x-12y=2
-12y=-4x+2
y=-4x/-12+2/-12
y=x/3-1/6 this line has a slope=1/3. (red line)
Thus a perpendicular line would have a slope=-3
-1=-3*10+b
-1=-30+b
b=-1+30
b=29 ans. for the y intercept.
y=-3x+29 (green line).
(graph 300x300 pixels, x from -6 to 25, y from -10 to 30, of TWO functions x/3 -1/6 and -3x +29).
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