SOLUTION: Find an equation of the line that has a y-intercept of -2 and is perpendicular to the graph of 3x+6y=2.

Question 244589: Find an equation of the line that has a y-intercept of -2 and is perpendicular to the graph of 3x+6y=2.
Answer by blwinbbbles(106) (Show Source): You can put this solution on YOUR website!
y = mx + b is the linear equation
b = y intercept so in this equation b = -2
so let's solve the given equation for it's slope
3x + 6y = 2 subtract 3x from both sides
6y = -3x + 2 divide both sides by 6
y = -3/6(x) + 2/6 or simplified y = -1/2(x) + 1/3
So we know the slope of the given line is -1/2....the slope of a line perpendicular to a given line is the inverse opposite sign...so the inverse opposite sign of -1/2 is + 2/1 or 2
So now we know b (the y intercept) and m (the slope) of the line: and the equation is:
y = 2x - 2
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