SOLUTION: Find the equation of the line that passes through the point (-2, 13) and is perpendicular to y = -2/5x + 3.
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Linear-equations
-> SOLUTION: Find the equation of the line that passes through the point (-2, 13) and is perpendicular to y = -2/5x + 3.
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The given equation is already in slope-intercept form, so you can determine the slope of the given line by inspection of the coefficient on .
Use the fact that perpendicular lines have slopes that are negative reciprocals of each other, that is:
to determine the slope of the desired line.
Now use the point-slope form of the equation of a line to write an equation of the desired line, that is:
where is the given point and is the slope you determined in the previous step.
You should ask your instructor or check for any instructions in your text as to the required final form of your answer such as slope-intercept or standard form.
Unfortunately, I cannot answer your question exactly as you stated it. One cannot find the equation of a line. That is because for any given set of ordered pairs that describe a straight line in a plane, there are an infinite number of equations that describe the relationship. The best anyone can ever do is provide an equation of a line.
