SOLUTION: Ummmmm hey i was wondering if u could help me on my hw, this problem says to: Find an equation of the line that passes through the point (-5,6)and is parallel to the line 2x-5y=-5.

Question 239652: Ummmmm hey i was wondering if u could help me on my hw, this problem says to: Find an equation of the line that passes through the point (-5,6)and is parallel to the line 2x-5y=-5.
a)-5x+6y=-5
b)2x+5y=-5
c)2x-5y=-40
d)2x-5y=37
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
: Find an equation of the line that passes through the point (-5,6)and is parallel to the line 2x-5y=-5.
:
Put the given equation in slope/intercept form to find the slope: (y = mx + b)
2x - 5y = -5
-5y = -2x - 5
Multiply by -1 to get a positive y
5y = 2x + 5
Divide both sides by 5
y = x +
y = .4x + 1
:
Parallel lines have the same slope; m=.4; x1=-5; y1=6
Use the point/slope form to write the equation of the parallel line:
that form is: y - y1 = m(x - x1)
;
y - 6 = .4(x - (-5))
y - 6 = .4(x + 5)
y - 6 = .4x +.4(5)
y - 6 = .4x + 2
y = .4x + 2 + 6
y = .4x + 8
:
In standard form
-.4x + y = 8
Get rid of the decimal, multiply by 5
-2x + 5y = 40
they want x to be positive, multiply equation by -1
2x - 5y = -40

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