SOLUTION: how do you solve y-2=1/3(y+6)?

Question 23436: how do you solve y-2=1/3(y+6)?
Found 2 solutions by stanbon, rapaljer:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y-2 = (1/3)y+2
(2/3)y=4
y = 4(3/2)= 6
Cheers,
Stan H>
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
I would multiply both sides of the equation by the denominator which is 3. That clears the fractions and makes life a little easier!

Now, get all the y terms to the left side by adding -y to each side.

Add +6 to both sides:

Check: Substituet y = 6 back into the original equation:

It checks!!

R^2 at SCC
RELATED QUESTIONS
how do you solve 1 + 5 / (y-1) =... (answered by jorel1380)
HOW DO YOU SOLVE FOR Y? 2x - y/2 = 1 -... (answered by macston,MathTherapy)
how do you solve... (answered by Alan3354)
How do you solve y = 6... (answered by College Student)
How do you solve: 2y/3-4=y/6-1... (answered by jim_thompson5910)
how do you solve: x/4 + y/4 = 1 -x/3 + y/2 -... (answered by ikleyn)
how do you solve, step by step,:... (answered by jim_thompson5910,vleith,Edwin McCravy)
how do you solve (x^2\16)+ (y^2\16)=1... (answered by stanbon!)
how do you solve: x>2+y y>1 (answered by ankor@dixie-net.com)