SOLUTION: 1). how would you find the slope that passes through the points of (-4 ,-1)and (-3 ,-3 )? and 2). find the slope of the graph 5x -3y = 6 3). simplify :(ab^4)(ab^2). 4). simpli

Question 2320: 1). how would you find the slope that passes through the points of (-4 ,-1)and (-3 ,-3 )? and
2). find the slope of the graph 5x -3y = 6
3). simplify :(ab^4)(ab^2).
4). simplify :[(m^3n^4)(m^2n^3)]/[(mn)(m^2n)]
5). solve:y=x+3
3y+x=5
6). simplify: [(3^2)^4]^2
please show me how to do these problems because i have some more to do.

Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
i have done gradients of straight lines before..look at my explanations there.
gradient is (change in y)/(change in x)
Re-arrange any straight line to y=mx+c..then m is the gradient.
so 5x-3y = 6
-3y = -5x+6 OR...
3y = 5x-6
y = (5/3)x-2
gradient is +5/3
3.
4.

5. linear equations... see the many examples i have done before.
6.

jon
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