SOLUTION: Help me solve this equation.Find the equation of the line through (-2,-9) and (0,-6).Write the equation in standard form.I have tried -9-(-6)

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Question 226454: Help me solve this equation.Find the equation of the line through (-2,-9) and (0,-6).Write the equation in standard form.I have tried -9-(-6)
-2-0 and i get -3/-2
so then i put it in -9=-3/2(-2)+b and i get y=-3/2x-12 and my final answer is 3x+2y=-24 but that is not one of the choices given to me. Can you tell me what is it that i'm doing wrong

Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
"-2-0 and i get -3/-2
so then i put it in -9=-3/2(-2)+b"

you have a sign problem
-3/-2 is 3/2 (the negatives cancel)
you use -3/2 in your equation

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Start with the slope formula.


Plug in , , , and


Subtract from to get


Subtract from to get


So the slope of the line that goes through the points and is


Now let's use and to find 'b'


Start with the general slope-intercept equation.


Plug in the given slope .


Plug in the and from the given point .


Multiply and to get


Add to both sides.


Combine like terms.


So the y-intercept is .


So the equation (in slope-intercept form) that goes through the points and is


If you need to convert it into standard form, then...


Start with the slope-intercept equation.


Multiply EVERY term by the LCD 2 to clear the fraction.


Subtract 3x from both sides.


Multiply EVERY term by -1 to make the x coefficient positive.


So the equation in standard form that goes through (-2,-9) and (0,-6) is


Here's a graph to visually confirm our answer:



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