SOLUTION: The perimeter of rectangular poster is 80 inch. The length is 10 inches greater than the width. Find the length.

Algebra.Com
Question 225266: The perimeter of rectangular poster is 80 inch. The length is 10 inches greater than the width. Find the length.
Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!
The perimeter of rectangular poster is 80 inch. The length is 10 inches greater than the width. Find the length.

Step 1. The perimeter P means adding up all the four sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let w+10 be the length since the length is 10 inches greater than the width

Step 4. Then, P=w+w+w+10+w+10=80.

Step 5. Solving yields the following steps

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: w=15.
  • Graphical form: Equation was fully solved.
  • Text form: w+w+w+10+w+10=80 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( w+w+w+10+w+10=80 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at .
Added fractions or integers together
It becomes .

Look at .
Moved 20 to the right of expression
It becomes .

Look at .
Eliminated similar terms highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+w+%29 replacing them with highlight_green%28+%281%2B1%2B1%2B1%29%2Aw+%29
It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Remove unneeded parentheses around factor highlight_red%28+4+%29
It becomes .

Look at .
Moved these terms to the left highlight_green%28+-80+%29
It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Removed extra sign in front of -60
It becomes .

Look at .
Solved linear equation highlight_red%28+4%2Aw-60=0+%29 equivalent to 4*w-60 =0
It becomes .
Result:
This is an equation! Solutions: w=15.

Universal Simplifier and Solver


Done!



For w=15 , then w+10=25 and P=2(15+25)=80 which is a true statement.

Step 6. ANSWER: The length is 25 inches.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

http://www.FreedomUniversity.TV
http://www.Facebook.com/FreedomUniversity.TV
http://www.Twitter.com/FreedomUTV

RELATED QUESTIONS

The length of a rectangular poster is 3 inches more than three times its width. Find the... (answered by macston)
The perimeter of a rectangular piece of poster board is 96in. The length is 8in. greater... (answered by ReadingBoosters)
Solve. The length of a rectangular poster is 7 in. greater than the width. the perimeter (answered by checkley77)
The area of a rectangle is the product of its length and width. Both the length and width (answered by ikleyn)
The length of a rectangular poster is 2 times its width . The area of the poster is 648... (answered by TimothyLamb)
the length of a rectangular poster is 5 inches longer than the width if. the permeter of... (answered by TimothyLamb)
The area of a rectangle is the product of its length and width. A rectangular poster has... (answered by ikleyn,josgarithmetic,MathTherapy)
The length of a rectangular photo is 2 inches greater than the width. The perimeter is 20 (answered by rfer)
the length of a rectangular photo is 2 inches greater than width. the perimeter is 20... (answered by Jolliano)