SOLUTION: Write the slope intercept form of the equation of the line described. through:(2,0), parallel to y=1/3x+3

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Question 224554: Write the slope intercept form of the equation of the line described.
through:(2,0), parallel to y=1/3x+3

Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!
Write the slope intercept form of the equation of the line described.
through:(2,0), parallel to y=x/3+3

Step 1. We can find the slope by recognizing that parallel lines have the same slope. Since is in slope-intercept form given as y=mx+b where the slope m=1/3 and the y-intercept b=3 when x=0 or at point (0,b) or (0,3).

Step 2. Now we have to find the line with slope m=1/3 going through point (2,0).

Step 3. Given two points (x1,y1) and (x2,y2), then the slope m is given as



Step 4. Let (x1,y1)=(2,0) or x1=2 and y1=0. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.

Step 5. Now we're given . Substituting above values and variables in the slope equation m yields the following steps:





Step 6. Multiply x-2 to both sides to get rid of denominator on right side of equation.





Step 7. ANSWER: The equation in slope-intercept form is


Note: the above equation can be rewritten as



And the graph is shown below which is consistent with the above steps.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -2/-1 = 2.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -2/3 = -0.666666666666667.
  • Slope is --1/3 = 0.333333333333333.
  • Equation in slope-intercept form: y=0.333333333333333*x+-0.666666666666667.



I hope the above steps and explanation were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV

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