SOLUTION: how can i graph a line that satisfies the conditions of passing through (2,-1) parallel to graph of 2x+3y=6

Question 222132: how can i graph a line that satisfies the conditions of passing through (2,-1) parallel to graph of 2x+3y=6

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
passing through (2,-1) parallel to graph of 2x+3y=6
3Y=-2X+6
Y=-2X/3+6/3
Y=-2X/3+2 THIS LINE HAS A SLOPE = -2/3. THEREFORE A PARALLEL LINE WILL ALSO HAVE A SLOPE=-2/3
-1=-2/3*2+b
-1=-4/3+b
b=-1+4/3
b=-3/3+4/3
b=1/3 the y intercept.
y=-2x/3+1/3
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10,-2x/3 +1/3).

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