SOLUTION: what is the equation of a line that is perpendicular to the graph of 3y-4x= -21, and goes through the point (-1,0).How do i write the answer in slope-intercept and standard form?

Question 221598: what is the equation of a line that is perpendicular to the graph of 3y-4x= -21, and goes through the point (-1,0).How do i write the answer in slope-intercept and standard form?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
what is the equation of a line that is perpendicular to the graph of
3y-4x= -21, and goes through the point (-1,0).How do i write the answer in slope-intercept and standard form?
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Given line: 3y-4x = -21
y = (4/3)x - 7
slope = 4/3
----------------------
Perpendicular Line?
slope = -3/4
Find intercept if y = 0 when x = -1.
y = mx + b
0 = (-3/4)(-1) + b
b = -3/4
-----------------
Equation:
y = (-3/4)x - 3/4
------------------------
Standard Form:
(3/4)x + y = -3/4
Multiply thru by 4 to get:
3x + 4y = -3
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Cheers,
Stan H.
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