SOLUTION: Find the equation of the line with is perpendicular to the line y=−8x+9, and which passes through the point (−16, 6). y=(1/8)x+b (6)=(1/8)(-16) + b -3=b y=(1/8)

Question 221407: Find the equation of the line with is perpendicular to the line y=−8x+9, and which passes through the point (−16, 6).
y=(1/8)x+b
(6)=(1/8)(-16) + b
-3=b
y=(1/8)x-3 <--- but this is wrong...
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
We can see that the equation has a slope and a y-intercept .

Now to find the slope of the perpendicular line, simply flip the slope to get . Now change the sign to get . So the perpendicular slope is .

Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope and the coordinates of the given point

.

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Add 6 to both sides.

Combine like terms.

So the equation of the line perpendicular to that goes through the point

is .

Here's a graph to visually verify our answer:

Graph of the original equation (red) and the perpendicular line (green) through the point

.

If you need more help or practice with this topic, check out this solver.

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SOLUTION: Find the equation of the line with is perpendicular to the line y=&#8722;8x+9, and which passes through the point (&#8722;16, 6). y=(1/8)x+b (6)=(1/8)(-16) + b -3=b y=(1/8)

SOLUTION: Find the equation of the line with is perpendicular to the line y=−8x+9, and which passes through the point (−16, 6). y=(1/8)x+b (6)=(1/8)(-16) + b -3=b y=(1/8)