SOLUTION: ok i have tried to keep up with my class. i go to an online high school and its hard for me to understand math i have searched my book and other resources but i can't figure out th

Question 220770: ok i have tried to keep up with my class. i go to an online high school and its hard for me to understand math i have searched my book and other resources but i can't figure out this problem. if you can provide any help or in-site that would be great
Question: A line perpendicular to x + 3y = 5 passes through (1,-1). What is the equation of the line in standard form.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A line perpendicular to x + 3y = 5 passes through (1,-1). What is the equation of the line in standard form.
:
Arrange the equation to slope intercept form to find the slope (m1)
x + 3y = 5
subtract x from both sides
3y = -x + 5
Divide both sides by 3
y = x +
;
The slope m1 =
The relationship of perpendicular lines is given by m1*m2 = -1
we know m1 = , find m2
*m2 = -1
Multiply both sides by -3
m2 = -3(-1)
m2 = +3
:
Use the point/slope formula to find the equation of the perpendicular line
y - y1 = m(x - x1)
Assign the values as follows: m=3; x1 = 1; y1 = -1
y - (-1) = 3(x - 1)
y + 1 = 3x - 3
y = 3x - 3 - 1
y = 3x - 4
Put in the standard form
3x - y = 4; is the equation of the perpendicular line
:
Did this make sense to you, any questions?
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