# SOLUTION: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is: So,

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is: So,       Log On

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 Click here to see ALL problems on Linear-equations Question 215483: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is: So, I got 3x + 2y = 4 2y = 4 - 3x y = (4 - 3x)/2 so m=2/3 then i plugged everything and got y - 7 = 2/3(x + 3) y - 7 = 2/3x + 2 y = 2/3x + 2 + 7 y = 2/3x + 9 Somehow its wrong, can anyone help? Thank you!Found 2 solutions by Alan3354, Earlsdon:Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!The equation of the line that goes through the point (3,7) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is: So, I got 3x + 2y = 4 2y = 4 - 3x y = (4 - 3x)/2 ************ y = (-3/2)x + 2 m = -3/2 -------- so m=2/3 ** That's the slope of lines perpendicular, the neg inverse of -3/2. Odd that you would have gotten the right answer using 2/3. ---------- then i plugged everything and got y - 7 = 2/3(x + 3) **************** y-7 = (2/3)(x - 3) You had (x+3) y - 7 = 2/3x - 2 y = (2/3)x - 2 + 7 y = (2/3)x + 5 Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Ok, you've got the slope of the new line correct. The negative reciprocal of the given line which has a slope: is, of course, Now you can write: In order to find b, the y-intercept, substitute the x- and y-coordinates of the point (3, 7) through which this line passes. Simplify. so... The final equation is: