SOLUTION: Write an equation in standard form with integral coefficents for the line thru the point (5,3) and parallel to the line Y= -7/6x+19

Question 215214: Write an equation in standard form with integral coefficents for the line thru the point (5,3) and parallel to the line Y= -7/6x+19
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Write an equation in standard form with integral coefficents for the line thru the point (5,3) and parallel to the line y= -7/6x+19

Step 1. An equation is in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept at point (0,b).

Step 2. Given has slope and y-intercept

Step 3. Parallel lines have the same slope so for our example.

Step 4. The parallel line must pass through point (5,3) or x=5 and y=3. To find the y-intercept b for this line we use the following equation,

Step 5. The equation for the parallel line in slope-intercept form is

Step 6. The equation of a line in standard form is defined as Ax+By=C where A, B, and C are constants.

Step 7. To put the equation in Step 5 in standard form, multiply 6 to both sides of the equation to get

Now add 7x to both sides of the equation to get it in standard form

Step 8. ANSWER: The equation of the parallel line is

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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