SOLUTION: The equation of the line that goes through the point ( 2 ,8 ) and is parallel to the line 3 x + 3 y = 4 can be written in the form y = mx+b where m is:
and where b is:
Please
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Question 215197: The equation of the line that goes through the point ( 2 ,8 ) and is parallel to the line 3 x + 3 y = 4 can be written in the form y = mx+b where m is:
and where b is:
Please help? Thank you :)
Found 2 solutions by Alan3354, drj:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The equation of the line that goes through the point (2,8) and is parallel to the line 3x + 3y = 4 can be written in the form y = mx+b where m is:
and where b is:
---------
Find the slope of 3x + 3y = 4 by putting it in slope-intercept form (that means solve for y).
3x + 3y = 4
3y = -3x + 4
y = -x + 4/3
Slope, m = -1
-------------
All parallel lines have the same slope.
Use y-y1 = m*(x-x1) where (x1,y1) is the point
y-8 = -(x-2)
y = -x + 10
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The equation of the line that goes through the point ( 2 ,8 ) and is parallel to the line 3 x + 3 y = 4 can be written in the form y = mx+b
Step 1. Let's rewrite 3x+3y=4 in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept.
slope-intercept form where and
Step 2. A parallel line to the one in Step 1 has the same slope or m=-1 for our example. This line needs to pass through (2,8) or x=2 and y=8. So we can use this to find b or the y-intercept.
Step 3. Our equation for the line is y=-x+10.
Here's the graph of the above situation;
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