SOLUTION: Find the equations in standard form with all coefficient integers of the line perpendicular to x + 3y = 6 and passing through (-3,3)

Algebra ->  Linear-equations -> SOLUTION: Find the equations in standard form with all coefficient integers of the line perpendicular to x + 3y = 6 and passing through (-3,3)      Log On


   

Question 208570: Find the equations in standard form with all coefficient integers of the line perpendicular to x + 3y = 6 and passing through (-3,3)
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x + 3y = 6
(a line perpendicular to & passing through (-3,3))
3Y=-X+6
Y=-X/3+6/3
Y=-X/3+2 THIS LINE HAS A SLOPE=-1/3.
A PERPENDICULAR LINE HAS A SLOPE=3
3=-3*3+b
3=-9+b
3+9=b
b=12 THE Y INTERCEPT OF THE PERPENDICULAR LINE.
Y=3X+12
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+20%2C+3x+%2B12%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 20, 3x +12).