SOLUTION: Find the general form of the equation of the line that passes through (-2,-5) and is perpendicular to the graph of 3x+2y=0
Can you please show me how to figure this out? I don't
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Question 207553This question is from textbook
: Find the general form of the equation of the line that passes through (-2,-5) and is perpendicular to the graph of 3x+2y=0
Can you please show me how to figure this out? I don't even know where to begin. Thank you so very much for your help and for your time.
This question is from textbook
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Subtract from both sides.
Divide both sides by to isolate y.
Simplify
We can see that the equation has a slope and a y-intercept .
Now to find the slope of the perpendicular line, simply flip the slope to get . Now change the sign to get . So the perpendicular slope is .
Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope and the coordinates of the given point
.
Start with the point slope formula
Plug in , , and
Rewrite as
Rewrite as
Distribute
Multiply
Subtract 5 from both sides.
Combine like terms. note: If you need help with fractions, check out this solver.
So the equation of the line perpendicular to that goes through the point
is .
Here's a graph to visually verify our answer:
Graph of the original equation (red) and the perpendicular line (green) through the point
.
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