SOLUTION: How do you put x-4=7 into slope-intercept form? This is what I tried already:
x-4=7
-x -x
-y=-x+4
Is that how you would do it? I don't think you can have a negative Y thou
Algebra.Com
Question 207181: How do you put x-4=7 into slope-intercept form? This is what I tried already:
x-4=7
-x -x
-y=-x+4
Is that how you would do it? I don't think you can have a negative Y though.
Found 2 solutions by mickclns, solver91311:
Answer by mickclns(59) (Show Source): You can put this solution on YOUR website!
This is the ONLY kind of linear equation that CANNOT be put in slope-intercept form, because it is a vertical line and has no slope (not a slope of 0, that is horizontal, but its slope is undefined) -- pick two points on a vertical line, the rise will be something, the run will be 0, so rise / run will be undefined -- you can't divide by 0.
x-4=7 --> x = 11. In other words, this is all of the points, (x,y), such that the x coordinate is 11.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Since there is no 
variable in your original equation, you cannot put the equation into slope-intercept form. In the first place, you can't just willy-nilly substitute for 
. There are points on the plane where and have the same value but they are NEVER the same thing. The only thing you can do with the given equation is add 4 to both sides, thus:
is the equation.
This equation represents the set of points where the -coordinate is 11, and the -coordinate is any real number value. In other words a vertical line that intersects the -axis at the point )
. As you should be aware, the slope of a vertical line is undefined, and a vertical line, except the one at 
is parallel to and never intercepts the -axis. So with an undefined slope and no -intercept, it is impossible to represent the equation in slope-intercept form.
John
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