SOLUTION: Write an equation of the line that passes through the points (-5,3) and (5,-3).

Question 200776: Write an equation of the line that passes through the points (-5,3) and (5,-3).
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point and is the second point .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Add 3 to both sides.

Combine like terms.

Remove the trailing zero

Simplify

So the equation that goes through the points and is

Notice how the graph of goes through the points and . So this visually verifies our answer.
Graph of through the points and

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(-5,3) and (5,-3)
First we need to find the slope (m) in the line equation Y=mX+b.
m=(y2-y1)/(x2-x1)
m=(-3-3)/(5+5)=-6/10 is the slope.
Now replacing the X+Y terms with one set of X & Y values we solve for the Y intercept (b).
3=-6/10*-5+b
3=30/10+b
b=3-30/10
b=3-3
b=0 which is the Y intercept.
Y=-6x/10 is the line equation which runs through the points (-5,3) & (5,-3).
Proof:
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -6x/10).

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