# SOLUTION: Find the equation in standard form of the line perpendicular to 2x-3y=-5 and passing through (3, -2). Write in standard form with all integer coefficients.

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: Find the equation in standard form of the line perpendicular to 2x-3y=-5 and passing through (3, -2). Write in standard form with all integer coefficients.      Log On

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 Click here to see ALL problems on Linear-equations Question 192096: Find the equation in standard form of the line perpendicular to 2x-3y=-5 and passing through (3, -2). Write in standard form with all integer coefficients.Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!2x-3y=-5 put into form y=mx+b subt 2x each side -3y=-2x-5 divide both sides by (-3) y=(2/3)x+5 m1 = 2/3, to be perpendicular m2= - 1/m1 = -3/2 writing the per ln eq in form y=mx+b y= (-3/2)x +b subst (3,-2) (-2)= (-3/2) (3) =b -2 = -9/2 +b add 9/2 to both sides -2 +9/2 =b 5/2=b or y=mx+b y= (-3/2)x +5/2 mult by 2 2y=-3x+5 add 3x to each side 3x+2y =5 ANSWER in standard form (Ax +By =C) check 3(3)+2(-2) = 5 ok