SOLUTION: Solve the system:
x - y + 3z = 23/2
3x + 2y + 2z = -6
2x - z = 1/2
Algebra.Com
Question 190106: Solve the system:
x - y + 3z = 23/2
3x + 2y + 2z = -6
2x - z = 1/2
Answer by ronak_hahs(1) (Show Source): You can put this solution on YOUR website!
Thus,by multiplying both sides by 2
....(1)
and
....(2)
By Adding 1 and 2 , we have
....(3)
Now we consider
Thus,by multiplying both sides by 2
....(4)
By Adding 3 and 4 , we have
i.e
Therefore putting value of x in 4,
i.e
Therefore putting value of x and z in 2,
i.e
i.e
i.e
Therefore
x=1 , y=-6 , z=3/2
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