SOLUTION: I got a question wrong on a test and I wasnt told what was wrong.
Identify the slop and y-intercept of the equation and graph.
2x - 2y = 6
I got 2y = 2x + 6
My teacher p
Algebra.Com
Question 187336: I got a question wrong on a test and I wasnt told what was wrong.
Identify the slop and y-intercept of the equation and graph.
2x - 2y = 6
I got 2y = 2x + 6
My teacher put the line on the graph which fell on (-1, -4), (1, -2), etc.
Why was the line put there? I got 4 out of 12 points but only for drawing the graph correctly (as in straight line, labeling x & y axis, etc).
Thanks
Answer by uday1435(57) (Show Source): You can put this solution on YOUR website!
For slope intercept form, we have to manipulate the terms such that only y has to come on the left side. Like y = mx+b
But you got 2y on the left side and not y. Even for that you made a mistake while rearranging the terms. Let us see how we do it
The original equation was 2x – 2y = 6 . The first step is to remove the 2x from the left side. This can be done by subtracting 2x on both sides
2x – 2y – 2x = - 2x +6
That gives - 2y = - 2x +6 . To isolate y on the left side we have to divide both sides by – 2
- 2y /(- 2) = (- 2x + 6) / -2
That is y = (-2/-2) x + (6/-2) means y = x – 3 which is the equation in slope intercept form. When we rewrite the equation in slope intercept form, The coefficient of x term (m) will be the slope and the last number (b) will be its y intercept. Here the coefficient =1. Similarly the last number ( ie. y intercept) is -3
So your answer is: Slope intercept form is y = x – 3, slope =1 and y intercept – 3
Your teacher drew the graph through (-1, 4), (1, -2) because the line passes through these points. Let us verify that
Eqn is y = x – 3 . Put x = -1 then y = - 1 – 3 = - 4 so (-1, -4 ) is a point on it.
Similarly put x = 1, y = x – 3 = 1 – 3 = - 2 so ( 1, - 2) also lies on it.
If you still require further clarifications please write to udayakumar.t.r@gmail.com
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