SOLUTION: Find the equation of the straight line that passes through the point (2,3) and is parallel to the line with equation 3x+4y-8=0.

Question 183578: Find the equation of the straight line that passes through the point (2,3) and is parallel to the line with equation 3x+4y-8=0.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of the straight line that passes through the point (2,3) and is parallel to the line with equation 3x+4y-8=0.
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Rearrange the given equation to see the slope-intercept form:
4y = -3x + 9
y = (-3/2)x + (9/4)
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The slope of that line is -3/2
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Your problem requires a slope of -3/2 and requires that y = 3 when x = 2.
The form is y = mx + b
You know m= -3/2 and y = 3 when x = 2; solve for "b".
3 = (-3/2)*2 + b
3 = -3 + b
b = 6
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Equation:
y = (-3/2)x + 6
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Cheers,
Stan H.
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