SOLUTION: Bobbi leaves biloxi, MS for Keokuk, Iowa at 6:00am, traveling at 50mph. two hours later, Pat leaves Keokuk, Iowa for Biloxi Traveling at 65 mph. These two city's are 560 miles apar

Question 183078: Bobbi leaves biloxi, MS for Keokuk, Iowa at 6:00am, traveling at 50mph. two hours later, Pat leaves Keokuk, Iowa for Biloxi Traveling at 65 mph. These two city's are 560 miles apart; and they will travel the same highway. when they meet who will have traveled the farther and by how much?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Bobbi leaves biloxi, MS for Keokuk, Iowa at 6:00am, traveling at 50mph. two hours later, Pat leaves Keokuk, Iowa for Biloxi Traveling at 65 mph. These two city's are 560 miles apart; and they will travel the same highway. when they meet who will have traveled the farther and by how much?
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Bobbi DATA:
rate = 50 mph ; time = x hrs ; distance = rt = 50x miles
---------------------------------------------
Pat DATA:
rate = 65 mph ; time = x-2 hrs ; distance = rt = 65(x-2)
------------------------------------------------
EQuation:
distance + distance = 560
50x + 65(x-2) = 560
115x - 130 = 560
115x = 690
x = 6 hrs (Bobbi time)
x-2 = 4 hrs (Pat time)
--------------------
Bobbi distance = 50x = 50*6 = 300 miles
--------
Pat distance = 65*(x-2) = 65*4 = 260 miles
========================================================
Cheers,
Stan H.
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