SOLUTION: Please help me solve this problem.
An equation in slope-intercept form for the line passing through each pair of points:
(9, -1) and 6, -2)
Thank you,
Doris
Algebra.Com
Question 182441: Please help me solve this problem.
An equation in slope-intercept form for the line passing through each pair of points:
(9, -1) and 6, -2)
Thank you,
Doris
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An equation in slope-intercept form for the line passing through each pair of points:
(9, -1) and 6, -2)
-----------------------
slope = (-1--2)/(9-6) = 1/3
--------------------------------
Line form is y = mx + b; you know y=-1 when x = 9 and m=1/3; solve for "b":
-1 = (1/3)(-1) + b
-1 = (-1/3) + b
b = -2/3
--------------------
Equation:
y = (1/3)x - (2/3)
========================
Cheers,
Stan H.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Please help me solve this problem.
An equation in slope-intercept form for the line passing through each pair of points:
(9, -1) and 6, -2)
------------------
The hard way:
Find the slope
slope, m, = diffy/diffx
m = (-1-(-2))/(9-6)
m = 1/3
--------------
Now use either point in
y-y1 = m*(x-x1) where (x1,y1) is the point
y-(-2) = (1/3)*(x-6)
y+2 = x/3 - 2
y = (1/3)x - 4
------------
------------
The easy way:
|x y +1|
|9 -1 1| = 0
|6 -2 +1|
- - - - -
x*(-1+2) - y*(9-6) +1*(-18+6) = 0
x -3y -12 = 0
x-3y = 12
x = 3y+12
y = (1/3)x - 4
|
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