# SOLUTION: Please help me with this equation how do I work this out? Consider the function {{{f(x) = x^2 + 4x + 1}}}. Find h, the x-coordinate of the vertex of this parabola.

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: Please help me with this equation how do I work this out? Consider the function {{{f(x) = x^2 + 4x + 1}}}. Find h, the x-coordinate of the vertex of this parabola.       Log On

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 Question 179521: Please help me with this equation how do I work this out? Consider the function . Find h, the x-coordinate of the vertex of this parabola. Found 2 solutions by jim_thompson5910, nerdybill:Answer by jim_thompson5910(28593)   (Show Source): You can put this solution on YOUR website!Note: From , we can see that , , and . In order to find the vertex, we first need to find the x-coordinate of the vertex. To find the x-coordinate of the vertex, use this formula: . Start with the given formula. Plug in and . Multiply 2 and to get . Divide. So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also . So consequently, (since "h" is the x-coordinate of the vertex) Answer by nerdybill(6958)   (Show Source): You can put this solution on YOUR website! The axis of symmetry can be found: -b/2a = -4/2 = -2 . Therefore, the x-coordinate of the vertex is -2