SOLUTION: equation of line with slope-1/2,passing thru point(-2,5)

Question 174565: equation of line with slope-1/2,passing thru point(-2,5)
Found 2 solutions by Mathtut, midwood_trail:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
point slope formula is y-k=m(x-h) where m is the slope and (h,k) is any point on the line.
:
y-5=-1/2(x+2)
:
y-5=-x/2-1...multiply each term by 2
:
2y-10=-x-2
:
x+2y=8
Answer by midwood_trail(310) (Show Source): You can put this solution on YOUR website!
Find an equation of the line with slope -1/2,passing thru point(-2,5).
Use the point-slope formula and then write equation in the y-intercept form.
y - y1 = m(x - x1)
y - 5 = (-1/2)(x - (-2))
y - 5 = (-1/2)(x + 2)
y - 5 = (-1/2)(x) - 1
y = (-1/2)(x) -1 + 5
y = (-1/2)(x) + 4
Understood?
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