SOLUTION: Find the standard form of the equation of the line that passes through the points (0, -1) and (8, 8).

Question 173087: Find the standard form of the equation of the line that passes through the points (0, -1) and (8, 8).
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Simplify

Subtract from both sides. Subtract 1 from both sides.

Rearrange the terms.

Multiply EVERY term by the LCD 8 to clear the fraction.

Multiply EVERY term by -1 to make the "x" coefficient positive.

So now the equation is in standard form where , , and
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the standard form of the equation of the line that passes through the points (0, -1) and (8, 8).
---------------------
I know 2 ways to do this.
One:
Find the slope, m
m = (diff in y)/(diff in x)
m = (8-(-1))/8
m = 9/8
Use either point
y-y1 = m*(x-x1)
y-8 = (9/8)*(x-8
y-8 = 9x/8 - 9
8y - 64 = 9x - 72
9x - 8y = 8
Two:
Use determinants
|x y +1|
|0 -1 1| = 0
|8 +8 1|
x(-1-8) - y(0-8) +(8) = 0
-9x +8y = -8
9x - 8y = 8

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