SOLUTION: Could you please help me with this problem? I have a hard time figuring out how to set up word problems... The perimeter of a picture frame is 11 feet. If three times the heig

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Question 171692: Could you please help me with this problem? I have a hard time figuring out how to set up word problems...
The perimeter of a picture frame is 11 feet. If three times the height is equal to eight times the width, what are the dimensions of the frame?
Thank you so much for your help...

Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let x=width and y=height


"The perimeter of a picture frame is 11 feet" translates to . Note: remember, the perimeter formula is where L and W are the length and width


"three times the height is equal to eight times the width" translates to


Start with the second equation


Divide both sides by 3 to isolate y


Go back to the first equation


Plug in


Multiply


Multiply EVERY term by the LCD 3 to clear the fraction.


Multiply and simplify


Combine like terms.


Divide both sides by 22 to isolate "x"


Reduce


So the first answer is (which in decimal form is )



Go back to the isolated equation


Plug in


Multiply 8 and to get


Reduce


So the second answer is



========================================================

Answer:


So the answers are (which in decimal form is ) and


This means that the width is 1.5 feet and the height is 4 feet.

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
All that's needed is the formula for perimeter
Let = perimeter
Let = height
Let = width
To find the perimeter, you start at a certain point
on the closed figure and go all the way around
returning to your starting point


Given:
ft


-----------------


Multiply both sides by


ft


ft
The frame is 4 ft high anf 1.5 ft wide
check:



OK

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