SOLUTION: Find the equation of the line that contains the points (-1,-2) and (-3,0) A. y=-x-3 B. y=x+3 C. y=1/2x-3/2 D. y=1/2x+3/2

Question 169806: Find the equation of the line that contains the points (-1,-2) and (-3,0)
A. y=-x-3
B. y=x+3
C. y=1/2x-3/2
D. y=1/2x+3/2
Found 2 solutions by jim_thompson5910, jojo14344:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Rewrite as

Distribute

Multiply

Subtract 2 from both sides.

Combine like terms.

Simplify

So the equation that goes through the points and is

Notice how the graph of goes through the points and . So this visually verifies our answer.
Graph of through the points and

Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
Given: (-1,-2) and (-3,0)
We get the ,
Via Point-Slope Form:
Subst.

.
Thru points (-1,-2):
Via Slope-intercept form:

.
Thru points (-3,0), should be the same:

--->
f(y)=0:

---->
So then, via Slope Intercept form:
, Answer (A)
See below,

Thank you,
Jojo

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