SOLUTION: How would I write an equation with a slope of -1/3

Question 167309: How would I write an equation with a slope of -1/3
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
slope intercept form of a linear equation is y = m*x + b
m is the slope.
b is the y intercept.
if you slope is -1/3, then the equation becomes:
y = -1/3*x + b
since you don't know anything else about the line, that's where you stop.
if you have a point on the line, then you can solve for b.
assume (1,3) is a point on the line.
(x,y) = (1,3)
x = 1
y = 3
substitute in your equation for y and x as follows:
y = -1/3*x + b
3 = (-1/3)*(1) + b
this becomes:
3 = -1/3 + b
adding 1/3 to both sides of the equation and it becomes:
3 + 1/3 = b
or:
10/3 = b
----
your equation now becomes:
y = -1/3x + 10/3
a graph of this equation looks like:
check below the graph for further comments.

your equation is:
y = -1/3x + 10/3
y intercept is the y value when x = 0.
y = 10/3 = 3 + 1/3 as you might be able to see on the graph. look for the value of y when x = 0.
you should also be able to see that when x = 1, y = 3.

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