SOLUTION: Need to solve: 1/2(2k-4)=3(k+2)-3k

SOLUTION: Need to solve: 1/2(2k-4)=3(k+2)-3k

Algebra.Com

Question 164367: Need to solve: 1/2(2k-4)=3(k+2)-3k
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
1/2(2k-4)=3(k+2)-3k
K-2=3K+6-3K
K-2=6
X=6+2
K=8
PROOF:
1/2(2*8-4)=3(8+2)-3*8
1/2(16-4)=3*10-24
1/2*12=30-24
6=6

RELATED QUESTIONS
I am asked to solve {{{(k)/(2k+2)}}}+{{{(2k-16)/ (4k+4)}}}={{{(k-3)/(k+1)}}} Thank... (answered by Edwin McCravy)

(k-3)/(k-2)-(k-4)/(k-1)=(3k+2)/(k^2-3k+2) (answered by Fombitz)

Solve for k: 5{(3-2k)+k}-6 = 2k-4(-3k-2)-12. Express your answer as a simplified... (answered by fractalier)

2k^2 - k + 3 + 5k^2 + 3k -... (answered by Alan3354)

7k+6/3k+4 = 3k+4/2k+1 solve the equation for the... (answered by Cromlix)

solve each equation 1/3 -k+3/6k = 1/3k - k-1/2k (answered by Fombitz)

2/3(3k-1)>3/2(2k-3) (answered by edjones)

how do you sovle... (answered by nerdybill)

please explaen me how to solve this equations 7n+2=4n+17... (answered by Earlsdon)