SOLUTION: Write an equation of the line containing the given point and parallel to the given line. (8,-2); 6x-7y=2 The equation of the line is y=__________

Algebra.Com
Question 160254: Write an equation of the line containing the given point and parallel to the given line.
(8,-2); 6x-7y=2
The equation of the line is y=__________

Answer by gonzo(654)   (Show Source): You can put this solution on YOUR website!
Write an equation of the line containing the given point and parallel to the given line.
(8,-2); 6x-7y=2
The equation of the line is y=__________
-----
the equation for the given line is 6*x - 7*y = 2
convert this to slope intercept form of the equation which is y = m*x + b
subtracting 6*x from both side of the equation gets -7*y = -6*x - 2
dividing both sides of the equation by (-7) gets y = (-6/-7)*x - (2/-7)
which becomes y = (6/7)*x - (2/7)
the slope of the line is (6/7) and the y intercept is -(2/7).
-----
you want a line with the same slope (parallel lines have the same slope) intersecting with the point (8,-2)
the slope intercept form of the equation going through the point (x1,y1) would be y = m*(x-x1) + y1
since (x1,y1) = (8,-2), then
x1 = 8
y1 = (-2)
since the slope is the same as the given line,
m = (6/7)
slope intercept form then becomes y = (6/7)*(x - 8) + (-2)
this becomes y = (6/7)*x - 8*(6/7) + (-2)
this becomes y = (6/7)*x - 48/7 - 14/7
this becomes y = (6/7)*x - (48+14)/7
this becomes y = (6/7)*x - (62/7)
to prove this equation is correct, substitute for x and y in the equation
y = (6/7)*x - (62/7) using the point (8,-2).
equation then becomes
-2 = (6/7)*8) - (62/7)
which becomes
-2 = 48/7 - (62/7)
which becomes
-2 = (48-62)/7
which becomes
-2 = -14/7
which becomes
-2 = -2
equation is good.
-----
slope intercept form of the equation is y = (6/7)*x - (62/7)
standard form of the equation would be a*x + b*y = c
to convert the slope intercept form to the standard form do the following:
y = (6/7)*x - (62/7)
multiply both sides by 7 to remove the denominators.
7*y = 6*x - 62
add 62 to both sides of the equation and subtract 7*y from both sides of the equation
62 = 6*x - 7*y
this is the same as 6*x - 7*y = 62 which is the standard form of the equation.
-----
a graph of both equations will look like this
please scan below the graph for additional comments

the lines are parallel and the graph of (6/7)*x - (62/7) intersects with the point (8,-2).

RELATED QUESTIONS

Write an equation of the line containing the given point and parallel to the given line (answered by checkley77)
how do you write an equation of the line containing the given point and parallel to the... (answered by checkley71)
write an equation of the line containing the given point and perpendicular to the given... (answered by nerdybill,checkley77)
Write an equation of the line containing the given points and parallel to the given line. (answered by solver91311)
Write an equation of the line containing the given point and parallel to the given line. (answered by ikleyn)
Write an equation of the line containing the given point and parrallel to the given line. (answered by Fombitz)
Write an equation of the line containing the given point and perpendicular to the given... (answered by stanbon,ewatrrr)
I am stuck, please help: Write an equation of the line containing the given point and... (answered by checkley77)
How do you write an equation of the line containing the given point and parallel to... (answered by MathLover1)