SOLUTION: Hi, my question is: how do you find the slope of two points when the coordinate of one of the points is a fraction? (5/3,-2) (3,6)

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Question 158284: Hi, my question is: how do you find the slope of two points when the coordinate of one of the points is a fraction?
(5/3,-2) (3,6)
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(30982) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, my question is: how do you find the slope of two points when the coordinate of one of the points is a fraction?
(5/3,-2) (3,6)
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The same way as when it's not a fraction.
m = (y2-y1)/(x2-x1)
m = (6 - (-2))/(3 - 5/3)
m = 8/(4/3)
m = 6

Answer by jim_thompson5910(28503) About Me  (Show Source):
You can put this solution on YOUR website!
The points and will be denoted and . So this means that , x%5B1%5D=5%2F3, y%5B1%5D=-2, x%5B2%5D=3, and y%5B2%5D=6



m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%286--2%29%2F%283-5%2F3%29 Plug in y%5B2%5D=6, y%5B1%5D=-2, x%5B2%5D=3, and x%5B1%5D=5%2F3


m=%288%29%2F%283-5%2F3%29 Subtract -2 from 6 to get 8


m=%288%29%2F%284%2F3%29 Subtract 5%2F3 from 3 to get 4%2F3 (ie 3-5%2F3=9%2F3-5%2F3=4%2F3)


m=%288%29%2A%283%2F4%29 Multiply the first fraction by the reciprocal of the second fraction.


m=6 Multiply and reduce.


So the slope of the line that goes through the points and is m=6