SOLUTION: Can you helf me find the parabola of the form Y=ax^2+bx+c (0,0),(-4,-36),(2,-18)

Question 151272: Can you helf me find the parabola of the form Y=ax^2+bx+c
(0,0),(-4,-36),(2,-18)
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
substituting (0,0) __ (0)=a(0)^2+b(0)+c __ 0=c

substituting (-4,-36) __ (-36)=a(-4)^2+b(-4) __ -36=16a-4b

substituting (2,-18) __ (-18)=a(2)^2+b(2) __ -18=4a+2b __ multiplying by 2 __ -36=8a+4b

adding equations __ -36+(-36)=16a-4b+8a+4b __ -72=24a __ dividing by 24 __ -3=a

substituting __ -18=4(-3)+2b __ adding 12 __ -6=2b __ dividing by 2 __ -3=b

Y=-3x^2-3x
RELATED QUESTIONS
A parabola y = ax^2 + bx + c has vertex (4, 2). If (2, 0) is on the parabola, then find... (answered by Fombitz)

Find the equation of the parabola {{{ y = ax^2 + bx + c }}} that passes through the... (answered by josgarithmetic)

Find an equation in the form y=ax^2+bx+c for the parabola passing through the points... (answered by MathLover1,greenestamps,ikleyn,Edwin McCravy)

Find the equation of parabola with the given condition: Axis vertical and passing... (answered by Edwin McCravy,josgarithmetic)

Can you please help me to sketch the graph, given is y=ax^2+bx+c where a<0 ; b<0 ; c<0... (answered by KMST)

In the accompanying diagram of the graph of the parabola y=ax�+bx+c, which must be one... (answered by Alan3354)

A parabola has vertex at (4, 6) and intersect the x-axis at x = 8. Find its equation in... (answered by nerdybill)

can someone please help me figure this out? Which of the following coefficients... (answered by scott8148,vleith)

A parabola with an equation of the form y = ax^2 + bx + c has the point (-2, 1) as its... (answered by Fombitz)