# SOLUTION: perpendicular to y=2/5x-11 and has a y-intercept of 2

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 Question 146848: perpendicular to y=2/5x-11 and has a y-intercept of 2Answer by nerdybill(6948)   (Show Source): You can put this solution on YOUR website!For a line to be perpendicular to another, their slopes must be "negative reciprocal". . Looking at: y=(2/5)x-11 It is in the form of "slope-intercept" form of: y = mx + b where m = slope b = y-intercept . Therefore we KNOW that the slope is 2/5. To find the "negative reciprocal": (2/5)x = -1 x = -5/2 . Now, we know the "slope" of the new line AND the problem said, it has a "y-intercept of 2" so, plug it all into: y = mx + b y = (-5/2)x + 2