SOLUTION: Hello, I am enrolled in a pre-algebra course online (so hard). Each week, we have to pick a "homework" problem from an approved list out of the current chapter in which we are wor

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Question 146674: Hello,
I am enrolled in a pre-algebra course online (so hard). Each week, we have to pick a "homework" problem from an approved list out of the current chapter in which we are working in. I have attempted to solve mine but I got stuck halfway through. I will type the problem just as it is stated in the textbook.
Demand equation. Helen's Health Foods usually sells 400 cans of ProPac Muscle Punch per week when the price is $5 per can. After experimenting with prices for some time, Helen has determined that the weekly demand can be found using the equation
d=600-40p,
where d is the numbe of cans and p is the price per can.
a) Will Helen sell more or less cans if she raises her price from $5?
b) What happens to her sales every time she raises her price by $1?
c)Graph the equation
d) What is the maximum price that she can charge and still sell at least one can?
I used the formula:
d=600-40 * 5 = 2800
d=600-40 * 6 = 3360
and so on, I don't know if this is right because if you increase the price, the demand increases, but wouldn't it be the other way around?
Thanks so much for your help :)

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
It is the other way around.
It's 600 - (40*5) = 400, and
600 - (40*6) = 360.
Multiply first, then subtract
-----------------
a) She'll sell fewer cans if the price goes up.
b) For each $1 increase, she'll sell 40 fewer cans.
c) Don't know how to do that here.
d) 600 - (40*Max) = 1
40*Max = 599
Max = 599/40 = $15 (to the nearest dollar), or $14.975.

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