SOLUTION: I am not sure when I subtract and when I add. I also get confused about where the signs (postive/negative) go. the question is Slope 1/3 through (1,6) y6= 1/3(x,1) 3 y

Question 146260: I am not sure when I subtract and when I add. I also get confused about where the signs (postive/negative) go.
the question is
Slope 1/3 through (1,6)
y6= 1/3(x,1)
3 y6= 3x 1/3 (x,1)
3y 18= 1x 3
3y +18-18= 1x 3-18
3y = 1x 21
x -3 =21
What am I doing wrong

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Are you trying to find the equation of a line with a slope of that goes through (1,6)?

If you want to find the equation of line with a given a slope of which goes through the point (,), you can simply use the point-slope formula to find the equation:

---Point-Slope Formula---
where is the slope, and

is the given point

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)

Distribute

Multiply and to get

Add 6 to both sides to isolate y

Combine like terms and to get (note: if you need help with combining fractions, check out this solver)

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Answer:

So the equation of the line with a slope of which goes through the point (,) is:

which is now in form where the slope is and the y-intercept is

Notice if we graph the equation and plot the point (,), we get (note: if you need help with graphing, check out this solver )

Graph of through the point (,)
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point (,), this verifies our answer.
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