SOLUTION: A line passing through (-4,4) and (x,-8) is perpendicular to a line with slope 5/12. Find the value of x.
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Question 139826: A line passing through (-4,4) and (x,-8) is perpendicular to a line with slope 5/12. Find the value of x.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A line passing through (-4,4) and (x,-8) is perpendicular to a line with slope 5/12. Find the value of x.
:
m1 = slope of the given coordinates
m2 = 5/12
;
We know that the relationship of the slopes of perpendicular lines is:
m1 * m2 = -1
m1 * = -1
Multiply equation by 12:
m1 * 5 = -12
m1 =
:
Using the slope formula; (y2-y1)/(x2-x1) = m:
=
:
You can see that x has to = 1, but here is the algebra to solve it:
=
neg on both sides:
=
cross multiply, solve for x:
12(x+4) = 12 * 5
12x + 48 = 60
12x = 60 - 48
12x = 12
x = 1
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