SOLUTION: Solve for x
x - 0.3(x + 10) = 4
x - 0.3x + 3 = 4
1x - 0.3x + 3 = 4
.7x + 3 = 4
.7x + 3 -3 = 4 -3 subtracted 3 on both sides
.7x/.7 = 1/.7
Algebra.Com
Question 134373: Solve for x
x - 0.3(x + 10) = 4
x - 0.3x + 3 = 4
1x - 0.3x + 3 = 4
.7x + 3 = 4
.7x + 3 -3 = 4 -3 subtracted 3 on both sides
.7x/.7 = 1/.7 divided by 7 on both sides
x = .7 Is this correct?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x - 0.3(x + 10) = 4
x - 0.3x - 3 = 4
0.7x = 7
x = 10
=========
Cheers,
Stan H.
RELATED QUESTIONS
The problem 7x+3<=7(x+1)has got me!
My best solution.
7x+3<=7(x+1)
= 7x+3<=7x+7... (answered by vleith)
Solve for x:... (answered by MathLover1)
x^4-7x^3+18x-126=0 (answered by Fombitz)
x^5+7x^4+10x^3=0 (answered by stanbon)
{{{3x^2-7x+4=(3x-4)(x-1)}}}
Two solutions:
{{{3x-4=0}}}
{{{3x=4}}}... (answered by Fombitz)
7x^3+10=... (answered by Fombitz)
Solve the following equation
log 7 + log(x − 1) − log(x^2 − 2) − (answered by Alan3354)
3x*(x^2+3x-28)/(x^4-3x^3+7x^2+11x-56)=0 (answered by stanbon)
Solve the following systems of equations and state if any lines are parallel
1. y +... (answered by math-vortex)