SOLUTION: Well, I have a test prep to do and chap. 7.1 review and this question stumps me and I can't figure out how to put the equations in an appropriate form so I can graph it. Because l

Question 130011This question is from textbook Algebra 1
: Well, I have a test prep to do and chap. 7.1 review and this question stumps me and I can't figure out how to put the equations in an appropriate form so I can graph it. Because like I know I have to put it in the y=mx+b form but the equation will have a fraction slope and I don't get that particular part. So can you please help me. This question is from textbook Algebra 1

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You don't necessarily need to put an equation into any particular form to sketch the graph, unless the test problem tells you that you have to plot one point and use the slope number to find a second point. Barring that, all you have to do is pick some value for x, plug that into the equation and then do the arithmetic to see what y has to be for that x. That gives you the coordinates of one point on the line. Then you do it all over again with another value for x and you have your second point. Draw a line through the two points and you are done.

Here's an example:

Pick a value for x. You can pick any value you like, so pick something that makes the arithmetic easy. I like to start with zero.

So the first point is (0,-3)

Do it all over again. Let's pick x = 1.

So the second point is (1,)

If you are supposed to plot one point, such as the y-intercept and then determine the next point using the slope, it is actually easier if your slope number is a fraction: You just start at the first point and go either right or left the number of units in the denominator of the slope and up or down the number in the numerator. If the slope number is positive, you go right and up or left and down. If the slope number is negative, you go right and down or left and up. Lines with positive slopes rise as you go left to right, lines with negative slopes fall as you go left to right.

In the example above, if you put the equation in to slope-intercept form you get: . If you plot the y-intercept, (0,-3) and then move right 4 (the denominator of the slope) and up (because the slope is positive) 3 (the numerator of the slope) you get to the point (4,0) which you can see is on the line.

There's not much more I can tell you without a specific equation to solve.

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