SOLUTION: 3. Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 2y = 8 and passing through (1, -6). First Step put in standard form wh

Question 129732This question is from textbook intermediate algebra
: 3. Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 2y = 8 and passing through (1, -6).

First Step put in standard form which is y = MX + B
X + 2Y = 8
TO DO THIS YOU WANT TO GET Y BY INSELF
x + 2Y = 8
-X -X SUBTRACT x fROM EACH SIDE ( * DO SAME THING TO BOTH SIDES)
2Y = 8-X NOW TO YOU MUST GET RID OF THE 2
/2 /2 DIVDE 2
Y = 4 - (1/2)X NOW YOU MUST ORDER THEM IN PROPER ORDER ( y = MX + B)
Y = -(1/2)X + 4 NOW YOU HAVE IT STANDARD FORM

NoW MAKE IT PERPENDICULAR BY GET RECPICROL OF THE SLOPE
WHICH IS 1
SO NOW YOUR EQUATION IS Y= X + 4
ORDER PAIR IT IS PASSING THROUGH ( 1,- 6 ) SO 1 IS x VALUE AND -6 IS Y VALUE
NEXT FORMULA Y -Y1 = M ( X - X1) M IS SLOPLE (1) AND Y1 AND X2 IS ORDER PAIR
PLUG IN Y - (6) = 1(X- (-6)) DISTRIBUTE
Y - (6) = 1X + 6 (* REMBEMBER TWO - - EQUALS A PLUS)
+6 ADD 6
fINAL ANSWER = Y = 1X + 6 OR Y = X + 6 ( YOU DONT NEED 1 BECAUSE THE LONE X STANDS FOR IT)

This question is from textbook intermediate algebra

Answer by torielisa17(4) (Show Source): You can put this solution on YOUR website!
3. Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 2y = 8 and passing through (1, -6).

First Step put in standard form which is y = MX + B
X + 2Y = 8
TO DO THIS YOU WANT TO GET Y BY INSELF
x + 2Y = 8
-X -X SUBTRACT x fROM EACH SIDE ( * DO SAME THING TO BOTH SIDES)
2Y = 8-X NOW TO YOU MUST GET RID OF THE 2
/2 /2 DIVDE 2
Y = 4 - (1/2)X NOW YOU MUST ORDER THEM IN PROPER ORDER ( y = MX + B)
Y = -(1/2)X + 4 NOW YOU HAVE IT STANDARD FORM

NoW MAKE IT PERPENDICULAR BY GET RECPICROL OF THE SLOPE
WHICH IS 1
SO NOW YOUR EQUATION IS Y= X + 4
ORDER PAIR IT IS PASSING THROUGH ( 1,- 6 ) SO 1 IS x VALUE AND -6 IS Y VALUE
NEXT FORMULA Y -Y1 = M ( X - X1) M IS SLOPLE (1) AND Y1 AND X2 IS ORDER PAIR
PLUG IN Y - (6) = 1(X- (-6)) DISTRIBUTE
Y - (6) = 1X + 6 (* REMBEMBER TWO - - EQUALS A PLUS)
+6 ADD 6
fINAL ANSWER = Y = 1X + 6 OR Y = X + 6 ( YOU DONT NEED 1 BECAUSE THE LONE X STANDS FOR IT)

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