SOLUTION:
c/2-d/5=-4 and c-d/5=-8 solve by substitution method
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Question 126976This question is from textbook algebra structure&method book 1
:
c/2-d/5=-4 and c-d/5=-8 solve by substitution method
This question is from textbook algebra structure&method book 1
Found 2 solutions by josmiceli, checkley71:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I notice that is common to both
add to both sides
add 8 to both sides
substitute this into
answer
answer
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
C-D/5=-8 OR C=D/5-8 OR C=(D-40)/5
[(D-40)/5)]/2-D/5=-4
(D-40)/5*1/2-D/5=-4
(D-40)/10-D/5=-4
(D-10-2D)/10=-4
(-D-10)/10=-4
-D-10=-40
-D=-40+10
-D=-30
D=30 ANSWER.
C-(30/5)=-8
C-6=-8
C=-8+6
C=-2 ANSWER.
PROOF:
-2-30/5=-8
-2-6=-8
-8=-8
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