SOLUTION: find the slope, if it exists, of (-1,-2), (3,-2)

Question 126066: find the slope, if it exists, of (-1,-2), (3,-2)
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Let's denote the first point (-1,-2) as . In other words, and

Now let's denote the second point (3,-2) as . In other words, and

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Start with the slope formula

Plug in ,,,

Subtract the terms in the numerator to get . Subtract the terms in the denominator to get

Reduce

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Answer:

So the slope of the line through the points (-1,-2) and (3,-2) is

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
SLOPE=(Y2-Y1)/(X2-X1)=(-2+2)/(3+1)=0/4=0 THIS IS A HORIZONTAL LINE THROUGH THE POINT Y=-2.
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