SOLUTION: Find the equation of the line through the egiven pair of points in standard form using only intergers. (5,1) and (-2,7)

Question 122776This question is from textbook college algebra
: Find the equation of the line through the egiven pair of points in standard form using only intergers.
(5,1) and (-2,7) This question is from textbook college algebra

Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First lets find the slope through the points (,) and (,)

Start with the slope formula (note: is the first point (,) and is the second point (,))

Plug in ,,, (these are the coordinates of given points)

Subtract the terms in the numerator to get . Subtract the terms in the denominator to get

Reduce

So the slope is

------------------------------------------------

Now let's use the point-slope formula to find the equation of the line:

------Point-Slope Formula------
where is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)

Distribute

Multiply and to get

Add to both sides to isolate y

Combine like terms and to get (note: if you need help with combining fractions, check out this solver)

Multiply both sides by 7 to clear the fractions

Add 6x to both sides
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
SLOPE=(7-1)/(-2-5)=6/-7=-6/7
7=-6/7*-2+b
b=7+12/7
b=(49+12)/7
b=61/7
Y=-6X/7+61/7 MULTIPLY ALL TERMS BY 7.
7Y=-6X+61

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