SOLUTION: Find solution to each system of equations by substitution I am still struggling using substitution method given 2 equations. Any help (detailed instructions) you can give me so

Question 121696This question is from textbook Elementary and Intermediate Algebra
: Find solution to each system of equations by substitution
I am still struggling using substitution method given 2 equations. Any help (detailed instructions) you can give me so i understand would be very much appreciated.
This is what I have gotten so far and its not working.
Problem: 6X+3Y=30 and 2X+3Y=18
2(30-3Y) over 6 = 3Y =18
60 + Y over 6 + 3Y =18
10/6 y =3y =18
5/3=3y =18
-3y=-5/3 +18
y = 5/3 +18
Then I lose it. Know its not right but don't know how to correct it.
It throws me when given a Y on one side and a X on the other side of the equation. How do i separate them? Then they throw a statement of multiply the equation by a number. Which number do I use? Then I run into another problem same as above only it has a -Y and a +Y number.
Problem: 1/2x + 2y = 5, 3X-1/2y =5 now I am dealing with fractions? Please help me.
Thank You. This question is from textbook Elementary and Intermediate Algebra

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The simple rule is: whatever you do to
one side of an equation, you have to do
to the other side
and
---------------------
What I see right away is I can divide both sides of the
1st equation by 3 without getting any fractions

Now, to get alone on the left side,
I subtract from both sides

Now I can substitute this for the
in the 2nd equation

Now add to both sides

Now subtract from both sides

divide both sides by
answer
Now you can use either equation to find

subtract from both sides

answer
You can check these answers by substituting
back into original equations
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